Therefore, ΔOAB is an equilateral triangle.Īrea of segment ACB = Area of sector OACB − Area of ΔOAB Question 6:Ī chord of a circle of radius 15 cm subtends an angle of 60° at the centre. Length of an arc of a sector of angle θ = (iii) Area of the segment forced by the corresponding chord Answer: (ii) Area of the sector formed by the arc In a circle of radius 21 cm, an arc subtends an angle of 60° at the centre. Let AB be the chord of the circle subtending 90° angle at centre O of the circle.Īrea of minor segment ACB = Area of minor sector OACB −Īrea of ΔOAB = 78.5 − 50 = 28.5 cm 2 Question 5: Therefore, the area swept by the minute hand in 5 minutes isĪ chord of a circle of radius 10 cm subtends a right angle at the centre. Therefore, the area swept by the minute hand in 5 minutes will be the area of a sector of 30° in a circle of 14 cm radius. We know that in 1 hour (i.e., 60 minutes), the minute hand rotates 360°. Find the area swept by the minute hand in 5 minutes. The length of the minute hand of a clock is 14 cm. Quadrant of circle will subtend 90° angle at the centre of the circle. Therefore, the area of the sector of the circle making 60° at the centre of the circle isįind the area of a quadrant of a circle whose circumference is 22 cm. Let OACB be a sector of the circle making 60° angle at centre O of the circle. Areas related to circle Page No 230: Question 1:įind the area of a sector of a circle with radius 6 cm if angle of the sector is 60°.
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